50 ml of water initially at 66 celcius is mixed with 43.5 ml of ice initially at 0 celcius. all the

50 ml of water initially at 66 Celcius is mixed with 43.5 ml of ice initially at 0 Celcius. All the ice melts and the mixture settles to a temperature of 3 Celcius. The specific heat of water is 1 cal/(gC). The density of water is 1 g/ml and the density of ice is 0.92 g/ml.

What is the mass (grams)nof originally warm water?

What is the mass (grams) of the ice ?

How much energy in calories is absorbed by the ice? It will be a positive number. Do not include energy needed to raise the melted ice water temperature from 0 to 3 Celcius

What is the experimental latent heat of fusion (cal/g) based on this data
mahdiwahib
Asked Mar 28, 2014

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