Answers please asap and explain how to do it

zero product rule-
2x^2+3x=(3x-1)^2-x^2


***^2 means squared

First I'll rewrite the equation properly:
2x²+3x=(3x-1)²-x²

Now we add x² to both sides and multiply out the (3x-1)²:
3x²+3x=9x²-6x+1

Then we subtract 3x² and 3x from both sides:
0=6x²-9x+1

Now using the quadratic equation (ax²+bx+c=0, y=(-b±√(b²-4ac))/2a):
(9±3√5)/12

So now we have:
(x-((9+3√5)/12))(x-((9-3√5)/12))=0

The zero product rule states ab=0 if a=0, b=0, or both of them =0, so if x= either (9+3√5)/12 or (9-3√5)/12 then the whole equation will equal 0.

So your answer is (9±3√5)/12