b. 20.1 g of MgS in 851 mL of soultion

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b. 20.1 g of MgS in 851 mL of soultion

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a.) 0.800 mol of Na2S in 1.55L of solutions.

Solution:- Molarity (M) = Moles of solute / Litres of solution

Molarity (M) = 0.800 moles of NA2S / 1.55 L of solution

= 0.516 moles/L

Solution:- Molarity (M) = Moles of solute / Litres of solution

Molarity (M) = 0.800 moles of NA2S / 1.55 L of solution

= 0.516 moles/L

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