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the sum of measures of all angles of a quadrilateral is 360

5x+4x+6y+3y=360

9x+9y=360

9[x+y]=360

x+y=40 dividing by 9

x=40-y

let y=20

then the value of x=20

then take any two values of y as y=20

then draw graph of this assumed values of x and y

there you will get point of intersection and it is the value of [x,y]

substitute it in 5x,4x,6y,3y

joint the points and you will get reqiuared quadrilateral

i hope you are understanding I dont know how to draw graph on computer

sorry for grammar mistakes

5x+4x+6y+3y=360

9x+9y=360

9[x+y]=360

x+y=40 dividing by 9

x=40-y

let y=20

then the value of x=20

then take any two values of y as y=20

then draw graph of this assumed values of x and y

there you will get point of intersection and it is the value of [x,y]

substitute it in 5x,4x,6y,3y

joint the points and you will get reqiuared quadrilateral

i hope you are understanding I dont know how to draw graph on computer

sorry for grammar mistakes

0

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