A student incorrectly reason that.
log a 1/x = log a x/xx= log[a](x)-log[a](x)[a](x)+log [a](x)=log [a](x)
What is the correct answer?
log a 1/x = log a x/xx= log[a](x)-log[a](x)[a](x)+log [a](x)=log [a](x)
What is the correct answer?
0

