About inequality solving problem

1)r/7>10 2)x/3>-1/3 3)-8>p/4 4)-48>6r 5)-3+x>-1
how do we solve this inequality problems?
mathu
Asked Dec 01, 2009
Edited Dec 01, 2009
1) Multiply both sides by 7. Since you're multiplying by a positive number, the sign stays the same, so it's r>70.

2) Same as the first one. x>-1.

3) It's the same as the first one, but in reverse. You can make it easier for yourself by flipping the entire problem, but be careful, you have to flip it as it is. So instead of -8>p/4, you can re-write it as p/4<-8. Now we do the same thing as the first one, so we get p<-32.

4) Same as 3, so r<-8.

5) This one is just simple adding. When adding or subtracting with equalities, the sign NEVER changes. So add 3 to each side to get x>2.

What I mentioned earlier about sign changing is, for example, if you had r/-7>10, you would be multiplying both sides by -7. Since we're multiplying by a negative number, the sign changes, so now it's r<-70. You'll have to know how to do this soon.
Oni_Kami
Answered Dec 02, 2009

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